Jiēféng 6
1. What isthe weight of the vessel (W) that is considered to act downwards through G?
A. The centre of gravity
B. The center of buoyancy
C. The center of floatation
D. The centerline
2. What is the force of buoyancy that is equal to W and acts upwards through B?
A. The centre of gravity
B. The center of floatation
C. The center of buoyancy
D. The centerline
3. An empty compartment amidships be holed below the waterline to such an extent that the water may flow freely into and out of the compartment. A vessel holed in this way is said to be ________.
A. punctured
B. bilged
C. drilled
D. flooded
4. What will happen to the buoyancy provided by the bilged compartment?
A. Gained
B. Transferred
C. Conserved
D. Lost
5. In the figure above, what will happen to the draftswhen the vessel now floats at the waterline W1L1, where it is again displacing its own weight of water?
A. The fore draft will increase which results trim by the head.
B. The aft draft will increase which results trim by the stern.
C. The draft will decrease evenly.
D. The draft will increase evenly.
6. From the figure above, which of the following is true?
A. The volume of lost buoyancy (v) is made good by the volumes ‘y’ and ‘z’.
B. The volume of lost buoyancy (x) is made good by the volumes ‘v’ and ‘z’.
C. The volume of lost buoyancy (y) is made good by the volumes ‘x’ and ‘v’.
D. The volume of lost buoyancy (z) is made good by the volumes ‘v’ and ‘x’.
7. Which of the following shows the increased in draft due to bilging?
A. Increased in draft is equal to the area of intact waterplane over the volume of lost buoyancy.
B. Increased in draft is equal to the volume of lost buoyancy over the area of intact waterplane.
C. Increased in draft is equal to the area of the bilged waterplane over the volume of lost buoyancy.
Increased in draft is equal to the volume of lost buoyancy over the area of the bilged waterplane
8. If this compartment is bilged, what will be the final draught?
A. 5.304 m
B. 5.542 m
C. 4.696 m
D. 5.589 m
9. What will be the change in GM?
A. 0.512 m reduction
B. 0.423 mreduction
C. 0.602 m reduction
D. 0.741 mreduction
10. If this compartment is bilged, what will be the sinkage?
A. 0.550 m
C. 0.615 m
B. 0.525 m
D. 0.635 m
11. What will be the draughts fore and aft if this compartment is bilged?
A. 10.625 m, 4.765 m
B. 10.485 m, 4.345 m
C. 10.655 m, 4.425 m
D. 10.595 m, 4.855 m
12. What will be the new mean draught?
A. 7.216 m
B. 7.189 m
C. 7.104 m
D. 7.255 m
13. What is the value of the shift of buoyancy (BB1)?
A. 0.658 m
B. 0.586 m
C. 0.699 m
D. 0.558 m
14. What is the moment of inertia of the bilged waterplane using parallel axis theorem?
A. 284135 m4
B. 298567 m4
C. 292457 m4
D. 282088 m4
15. What will be the GM?
A. 3.845 m
C. 3.731 m
B. 4.125 m
D. 4.565 m
16. What will be the angle of heel?
A. 9 degrees
B. 10 degrees
C. 11 degrees
D. 12 degrees
17. ____ is the amount of water that can enter a compartment or tank after it has been bilged.
A. Permeability
C. Flooding
B. Bilging
D. Grounding
18. The value of ____ does not change throughout the bilging process since there is no weight added, discharged or transferred.
Gm
Kg
Km
Kb
19. Which of the following is true?
A. The lower the value of the permeability for a bilged compartment, the greater will be a ship’s loss of buoyancy when the ship is bilged.
B. The higher the value of the permeability for a bilged compartment, the lower will be a ship’s loss of buoyancy when the ship is bilged.
C. The higher the value of the permeability for a bilged compartment, the greater will be a ship’s loss of buoyancy when the ship is bilged.
D. The higher the value of the permeability for a bilged compartment, the greater will be a ship’s loss of permeability when the ship is bilged.
20. A box-shaped vessel 100 metres long x 20 metres wide x 12 metres deep is floating in salt water on an even keel at 6 metres draft. A forward compartment is 10 metres long, 12 metres wide and extends from the outer bottom to a watertight flat, 4 metres above the keel. The compartment contains cargo of permeability 25 per cent. What will be the new drafts if this compartment is bilged?
A. Aft 6.15 m, Fore 6.32m
B. Aft 6.25 m, Fore 6.42m
C. Aft 5.90 m, Fore 6.22m
D. Aft 5.75 m, Fore 6.12m
21. As the water level falls in the drydock there is no effect on the ship’s stability so long as the ship is completely waterborne, but after the stern lands on the blocks ____________.
A. The draft aft will decrease and the trim will change by the head.
B. The draft forward will decrease, and the trim will change by the stern.
C. Both a and b.
D. Neither a nor b.
22. It is the interval of time between the stern post landing on the blocks and the ship taking the blocks overall.
A. Critical period
B. Upthrust phase
C. Grounding period
D. Docking phase
23. What will happen when positive effective metacentric height cannot be maintained throughout the drydocking period?
A. The ship will destroy the blocks since it cannot hold the weight of the ship.
B. The ship will heel over and perhaps slip off the blocks with disastrous results.
C. The propeller will be destroyed since it will be the first to land when there is no positive stability.
D. All of the above.
24. What is the initial hydrostatic draft?
A. 4.100 m
B. 4.267 m
C. 4.302 m
D. 4.067 m
25. What is the upthrust force?
A. 438.2 T
B. 428.3 T
C. 483.2 T
D. 432.8 T
26. What is the new displacement?
A. 7369.9 T
B. 7639.9 T
C. 7939.9 Td.
D. 7396.9 T
27. What is the value of KM from the new displacement?
A. 9.778 m
B. 9.887 m
C. 9.798 m
D. 9.878 m
28. What is the GM fluid?
A. 0.724 m
B. 0.742 m
C. 0.774 m
D. 0.747 m
29. What is the virtual loss of GM?
A. 0.509 m
B. 0.806 m
C. 0.608 m
D. 0.580 m
30. Which of the following will be course of action possible to increase the GM at Critical Instant?
A. Increase the GM by lowering weights or ballasting a double bottom.
B. Reduce the initial trim by transfer or ballasting so that the loss of GM is reduced.
C. Both a and b.
D. Neither a nor b.
31. What is the reduction of pressure energy which causes the vessel to sink further and the UKC reduces?
A. Squat
B. Trim
C. Sinkage
D. Grounding
32. What is the law that governs this phenomenon of the vessel’s sinkage due to the reduction of pressure?
A. Newton’s Law
B. Galileo’s Law
C. Bowditch’s Law
D. Bernoulli’s Law
33. Along with the reduction in UKC, what other particulars changes?
A. Vessel’s trim also changes
A. Vessel’s displacement also changes
B. Vessel’s center of gravity also changes
C. Vessel’s metacentric height also changes
34. The reduction in UKC varies approximately with the square of _____.
A. Ship’s speed
B. Ship’s inertia
C. Ship’s draft
D. Ship’s block coefficient
35. Vessels having higher block coefficient will also have a higher ______.
A. Trim
B. Squat
C. Freeboard
D. Speed
A container ship has a Cb of 0.575 and is proceeding at a speed of 6 kts. When static, the ship was on even keel. 36. What is the squat of the ship in open waters?
A. 0.207 m
B. 0.306 m
C. 0.405 m
D. 0.504 m
A container ship has a Cb of 0.575 and is proceeding at a speed of 6 kts. When static, the ship was on even keel. 37. What is the squat of the ship in shallow waters?
A. 0.414m
B. 0.612 m
C. 0.810 m
D. 1.008 m
A container ship has a Cb of 0.575 and is proceeding at a speed of 6 kts. When static, the ship was on even keel. 38. What is the squat if the constant K value = 1.752?
A. 0.343 m
B. 0.383 m
C. 0.363 m
D. 0.323 m
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full. 39. What is the VCG of the ballast tank at ¼ full?
A. 0.50 m
B. 1.01 m
C. 0.75 m
A. 0.75 m
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full. 40. What is the distance between ship’s COG and the tank’s COG when flooded at ¼ full?
A. 9.4 m
B. 9.5 m
C. 9.6 m
D. 9.7 m
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.41. What is the change of position of ship’s center of gravity due to added weight?
A. 0.903 m
B. 0.093 m
C. 0.309 m
D. 0.039 m
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.42. What will be the KG after flooding?
A. 9.993 m
B. 9.708 m
C. 9.807 m
D. 9.939 m
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.43. The KG after flooding indicates that the GM increased due to __________.
A. Added weights below the ship’s center of gravity.
B. Free surface effect of the water inside the tank.
C. Lost of buoyancy of the tank.
D. In and out of water inside the tank.
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.44. What is the final KG after applying free surface effect?
A. 9.397 m
B. 9.937 m
C. 9.739 m
D. 9.973 m
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.45. This process considers the flooded water to be a weight added to a certain point in the ship. It provides more accurate results and is hence used by most stability analysis software?
A. Added Weight Method
B. Lost Buoyancy Method
D. Free Surface Correction Method
C. Permeability Method
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.46. How can the subdivision of a ship preserves it buoyancy?
A. A ship is divided transversely into a number of watertight compartments to restrict the flooding to one or more compartments in case of damage
B. A ship is divided longitudinally into a number of watertight compartments to restrict the flooding to one or more compartments in case of damage
C. This prevents progressive flooding across the entire ship’s breadth in case of a damage at any location.
D. All of the above.
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.47. In Figure No. 2, which of the following indicates that the margin line would submerge if the following compartments were flooded together?
A. Both CD and DE.
B. Both DE and EF.
C. Both BC and CD.
D. Both AB and EF.
A boxed shaped vessel floating on an even keel in saltwater has the following particulars: Displacement = 20,000 T Length = 146 m Breadth = 29.4 m Draught = 6.52 m KG = 9.90 m FSM=2621.43 The vessel has a ballast tank with a full capacity of 800 T and is empty. The vertical center of gravity of the tank is 2.0 m. An allision happened and the tank was flooded with seawater ¼ full.48. In Figure No. 2, the margin line would remain above the waterline for simultaneous flooding in which following compartments?
A. Both CD and DE.
B. Both AB and BC.
C. Both BC and CD.
D. Both EF and FG.
49. It is the maximum portion of the ship’s length with the point ‘P’ at the center that can be completely flooded symmetrically without immersing the margin line.
B. Permissible length
A. Floodable length
C. Permeable length
D. Longitudinal length
50. This method assumes that the damaged compartment does not contribute to the total buoyancy of the ship. Hence, the ship loses a part of its total waterplane, and its buoyancy, therefore reducing stability.
A. Added Weight Method
B. Lost Buoyancy Method
C. Permeability Method
D. Free Surface Correction Method
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