Computer Architecture Quiz 2

Amount of time that is required to execute specific task

Computer A takes 200 sec to execute a given task, the same task is executed in 20 sec with computer B. How many times A faster than B

Computer A takes 200 sec to execute a given task, the same task is executed in 20 sec with computer B. How many times B faster than A

Computer A takes 100 sec to execute a given task, the same task is executed in 10 sec with computer B. How many Times B Faster Than A

Replace the CPU in a single user system with a new improvement one will :

Sub times that occur inside the CPU are :

Sub times that occur outside the CPU are :

The real time that the process spend inside the CPU.

The time that is called (User Time) :

The time that is called (System Time) :

In the Process Life Cycle, after the proccess is ready in the waiting queue it enters cpu for execution

In the Process Life Cycle, after the proccess is ready in the waiting queue it enters ready queue

Unit of Clock Rate is :

Unit of clock cycle time

Compute clock cycle time for a CPU that has clock rate 3.12 GHz

Compute clock rate for a CPU that has clock cycle time 0.7 * 10^-6 Second

Assume that multiply instructions take 20 cycles and account for 45% of the instructions in typical program and other 55% instructions require on average 6 cycles for each instructions. What percentage of time-does the CPU spends in multiply instructions

Assume that x instructions take 10 cycles and account for 20% of the instructions ,y instructions take 30 cylces for 45% of the instructions , z takes 15 cycles for 35% of the instructions. Calculate the average CPI

Let we have a process with 600instructions, we look to execute it on a system with C.R 2000 MHz at CPI 13. Compute process execution time

One process takes 65 sec to be executed. 45% of time works in multiplication. We look to improve the multiplication 12 time . Compute new execution time and speed up

Increasing CPI will increase Mega Floating Points Operations

Increasing response time will decrease bandwidth

For a given architecture performance improvement comes from:

Increasing clock rate will improve performance.

The lower value of million instructions per second (MIPS) is the best

The measure of computing ammount improvment is called bandwidth

The measure of computing ammount improvment is called Cpu Time

The measure of computing ammount improvment is called Speed Up

Replace a proccessor with a new faster one will increase the delay time

Decreasing CPI will increase MIPS

Increasing CCT will increase the performance

Decreasing CPU time will increase the performance