Automata - Finals

A TM accepts language generated by ___________.
Type 0 grammars
Type 1 Grammars
Type 3 Grammars
Verifies the text's syntax
Parser
Input tape
Reading head
Finite control
Stack
Contains specific number of squares that contain a single input symbol. Strings placed is traversed from left to right
Parser
Input tape
Reading head
Finite control
Stack
Scans each square in the input tape and reads input from the tape. Moves from left to right.
Parser
Input tape
Reading head
Finite control
Stack
Serves as the control unit of the PDA. Decides which state the pda will move and which stack symbol it will push or pop
Parser
Input tape
Reading head
Finite control
Stack
Temporary storage of stack symbols. Allows pda ro recognize some non regular languages.
Parser
Input tape
Reading head
Finite control
Stack
Describes the configuration of the PDA at a given instance. It remembers tha state's information at a given instance of time.
Instantaneous description
Acceptance by final state
Acceptance by empty stack
String can be declared as accepted after the total traversal of the input string the pda enters into its final state
Instantaneous description
Acceptance by final state
Acceptance by empty stack
String can be declared as accepted by an empty stack if all the input characters, the stack is empty after reading the rightmost input character
Instantaneous description
Acceptance by final state
Acceptance by empty stack
Describes the current state
Q
W
S
Describes the remaining/unconsumed input
Q
W
S
Describes the stack contents (the leftmos symbol corresponds to the top of the stack and the rightmost symbol is the bottom element)
Q
W
S
No creativity implies that each step in the calculation must be fully spelled out
True
False
The list of instructions followed must be infinite
True
False
Each individual step in the calculation must take an infinite amount of time to complete
True
False
Intermediate results may need to be calculated, so a scratch-pad area is needed
True
False
There is no need to keep track of the current step of the calculation
True
False
There must be a way to keep track of the current state of the calculation
True
False
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